Inverter 430 alarm fault code F0002 problem? -Solutions - Huaqiang Electronic Network

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A 5.5KW inverter is used to control a 5.5KW booster pump. The system is set up very carefully, allowing it to run continuously for approximately 15 days before an error code F0002 appears. After disconnecting and reconnecting the circuit breaker in front of the inverter, the system returns to normal operation. What could be causing this issue? Also, what is the appropriate ramp-down time that should match the inertia of the load?

A: Regarding the F0002 fault:
1. F0002 indicates an overvoltage fault.
2. Possible causes:
- The DC link voltage exceeds the trip threshold.
- Overvoltage may occur if the power supply voltage is too high or if the motor is in regenerative braking mode.
- The ramp-down speed is too fast, or the motor is being driven by a large inertia load, which causes it to enter a regenerative braking state.
3. Recommended solutions:
- Check the motor’s power cables and grounding for any breaks or improper connections.
- Adjust the ramp parameters P1120 and P1121 on the inverter to increase their values.
- Ensure a brake resistor is properly configured. If not, set parameter P1240 to 1. If a brake resistor is installed, set P1240 to 0.
4. In general, inverters tend to report under-voltage faults when the frequency increases, while overvoltage faults often occur during deceleration or braking. If the inverter's input voltage is too high, it can also trigger the F0002 error.

It’s important to ensure the inverter settings are optimized for the specific load conditions. If the system is frequently experiencing overvoltage issues, consider reviewing the motor’s mechanical inertia and adjusting the ramp times accordingly. This will help prevent unnecessary trips and improve the overall stability of the system.

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